$(1)$
付表2より,圧力$0.101325$の値を読み,
\[
v' = 0.00104344 \,\textrm{m}^3\textrm{/kg}, \ \ v' ' = 1.67330 \,\textrm{m}^3\textrm{/kg} \\
\therefore\frac{v' ' }{v'}= \frac{1.6733}{0.00104344} = 1604\,倍
\]
$(2)$
付表2より,
\[
T_s=99.974^\circ \textrm{C}
\]
$(3)$
付表2より,
\[
h'=418.99\,\textrm{kJ/kg}\\
h' ' =2675.53\,\textrm{kJ/kg}\\
s'=1.30672\,\textrm{kJ/kg}\\
s' '=7.35439\,\textrm{kJ/kg}
\]
$(4)$
\[
r=h' ' - h' より \\
r=2256.54\,\textrm{kJ/kg}
\]