\[ V=\frac{π}{4}(0.06)^2\times 0.03=8.482\times 10^{-5}\, \rm{m^3} \] \[ \upsilon=\frac{V}{m}=\frac{8.482\times 10^{-5}}{0.11\times 10^{-3}}=0.771\, \rm{m^3/kg} \] \[ \rho=\frac{1}{\upsilon}=1.2968=1.30\, \rm{kg/m^2} \]