$25\rm{^\circ C}$の空気$ \ \Longrightarrow \ $$\rho=1.184\,\rm{kg/m^3}$,$\mu=1.832\times10^{-5}\,\rm{Pa\cdot s}$
$(1)$
\[
\begin{align}
Re=\frac{\rho\upsilon d}{\mu}
&=\frac{1.184\,\rm{kg/m^3}\times30\,\rm{m/s}\times10\times10^{-2}\,\rm{m}}{1.832\times10^{-5}\,\rm{Pa\cdot s}}\\
&=1.93\times10^5
\end{align}\]
\[
2340以上なので乱流
\]
$(2)$
$Re=1\times10^5~3\times10^6$の範囲にあるので
\[
\begin{align}
\lambda
&=0.0032+0.221\ Re^{-0.237}\\
&=0.0032+0.221\times\left(1.93\times10^5\right)^{-0.237}\\
&=0.0156
\end{align}
\]
$(3)$
\[
\begin{align}
\Delta P=\lambda\frac{l}{d}\frac{\rho\upsilon^2}{2}
&=0.0156\times\frac{10\,\rm{m}}{10\times10^{-2}\,\rm{m}}\times\frac{1.184\,\rm{kg/m^3}\times\left(30\,\rm{m/s}\right)^2}{2}\\
&=831\,\rm{Pa}
\end{align}\]